Answer:
x ≥ [tex]\frac{5}{2}[/tex]
Step-by-step explanation:
Given equation:
4x² -20x + 25≥0
To solve for x, we simply factorize the equation;
We should find two numbers whose sum = -20 and product is 100
These two numbers are -10 and -10
So;
4x² - 10x - 10x + 25 ≥ 0
factorize;
2x(2x - 5) - 5(2x - 5) ≥ 0
(2x - 5) (2x - 5) ≥ 0
So;
2x - 5 ≥ 0
2x ≥ 5
x ≥ [tex]\frac{5}{2}[/tex]
