Answer:
The correct option is;
b) 60 cal
Explanation:
The mass of the given water, m = 12 g
The initial temperature of he given water = 16°C
The final temperature of the given water = 21°C
The specific heat capacity of water, c = 4.184 J/(g·°C) = 1 cal/(g·°C)
The amount of heat, ΔQ, required = Mass × Specific heat capacity × Change in temperature
ΔQ = 12 × 4.184 × (21 - 16) = 251.04 J
Similarly, we have;
ΔQ = 12 g × 1 cal/(g·°C) × (21 - 16)°C = 60 cal
The amount of heat required = 60 cal.
