tdwivan
tdwivan tdwivan
  • 20-10-2020
  • Mathematics
contestada

If m CDE=(3x+10)° m CDF=(x+25)°, and m EDF= 65°. Find m CDF​

If m CDE3x10 m CDFx25 and m EDF 65 Find m CDF class=

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LadyStrange
LadyStrange LadyStrange
  • 20-10-2020

m∠CDF + m∠EDF = ∠CDE

[tex]x + 25° + 65° = 3x + 10[/tex]

[tex]x + 90° = 3x + 10[/tex]

[tex]90° = 3x + 10 - x[/tex]

[tex]90° = 2x + 10[/tex]

[tex]2x + 10 = 90[/tex]

[tex]2x = 90 - 10[/tex]

[tex]2x = 80[/tex]

[tex]x = \frac{80}{2} [/tex]

[tex]x = 40°[/tex]

m∠CDE

= 3 × 40 + 10

= 120 + 10

= 130°

Then , m∠CDF =

[tex]x + 25 \\ = 40 + 25 \\ = 65°[/tex]

•°• m∠CDF = 65°

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