Given :
A rectangular yard measuring 39 ft by 63 ft is bordered (and surrounded) by a 2 ft fence.
To Find :
The area of this walk.
Solution :
Area of whole park :
[tex]A=39\times 63\ ft^2\\\\A=2457\ ft^2[/tex]
Now, length and breadth after removing the fences is l = 63 - 2( 2) = 59 ft and b = 39 - 2( 2 ) = 35 ft.
Area of inner park :
A' = 35 × 59 ft²
A' = 2065 ft²
Therefore, area of fencing is 2457 - 2065 = 392 ft² .
Hence, this is the required solution.
