racheltorres8729 racheltorres8729
  • 18-11-2020
  • Mathematics
contestada

Consider the following discrete probability mass function.

x 3 1 –1
P(X = x) 0.25 0.30 0.45

Find P(X ≥ 1).

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 22-11-2020

Answer:

[tex]P(x \geq 1) = 0.55[/tex]

Step-by-step explanation:

Given:

x --------------3 ---------1 ------- –1

P(X = x) --- 0.25 ---0.30 ---- 0.45

Required

Calculate [tex]P(x \geq 1)[/tex]

[tex]x \geq 1[/tex] implies that x = 1,2,3,4......

So:

[tex]P(x \geq 1) = P(x = 1) + P(x = 3)[/tex]

From the above table

[tex]P(x = 1) = 0.30[/tex]

[tex]P(x = 3) = 0.25[/tex]

Substitute these values in [tex]P(x \geq 1) = P(x = 1) + P(x = 3)[/tex]

[tex]P(x \geq 1) = 0.30 + 0.25[/tex]

[tex]P(x \geq 1) = 0.55[/tex]

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