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Which of the following is the graph of y = StartFraction 1 Over x + 2 EndFraction + 1?
On a coordinate plane, 2 curves are shown. Both curves have an asymptote at x = 2. One curve opens up and to the right in quadrant 1. The other curve opens down and to the left and it crosses the x-axis at (1, 0).
On a coordinate plane, 2 curves are shown. Both curves have an asymptote at x = 2. One curve opens up and to the right in quadrants 1 and 4. It crosses the x-axis at (3, 0). The other curve opens down and to the left and it crosses the y-axis at (0, negative 1.5).
On a coordinate plane, 2 curves are shown. Both curves have an asymptote at x = negative 2. One curve opens up and to the right in quadrants 1 and 2. It crosses the y-axis at (0, 1.5). The other curve opens down and to the left and it crosses the x-axis at (negative 3, 0).
On a coordinate plane, 2 curves are shown. Both curves have an asymptote at x = negative 2. One curve opens up and to the right in quadrants 1, 2, and 4. It crosses the x-axis at (negative 1, 0). The other curve opens down and to the left in quadrant 3.

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sanaritaokii

Answer: C

Step-by-step explanation:

Use the graph ln the left side.

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MrRoyal

The description of the graph of the function [tex]y = \frac{1}{x + 2} + 1[/tex] is the description (c)

How to determine the graph of the equation?

The equation is given as:

y = StartFraction 1 Over x + 2 EndFraction + 1?

Rewrite properly as:

[tex]y = \frac{1}{x + 2} + 1[/tex]

The above equation is the translated equation from an inverse function

The graph of the function pass through the points (0,1.5) and (-3,0)

Hence, the graph of f(x) = √x is (c) On a coordinate plane, 2 curves are shown. Both curves have an asymptote at x = -2. One curve opens up and to the right in quadrants 1 and 2. It crosses the y-axis at (0, 1.5). The other curve opens down and to the left, and it crosses the x-axis at (-3, 0).

Read more about functions at:

https://brainly.com/question/4025726

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