Kingmoney4516 Kingmoney4516

20-11-2020
Chemistry

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What volume of a 0.311 M hydrochloric acid solution is required to neutralize 13.9 mL of a 0.110 M potassium hydroxide solution?

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maacastrobr maacastrobr

24-11-2020

Answer:

4.9 mL

Explanation:

To answer this question we will use the following equation:

C₁V₁=C₂V₂

Where the subscript 1 refers to hydrochloric acid, while 2 refers to potassium hydroxide. Meaning:

C₁ = 0.311 M

V₁ = ?

C₂ = 0.110 M

V₂ = 13.9 mL

So we solve for V₁:

0.311 M * V₁= 0.110 M * 13.9 mL

V₁ = 4.9 mL

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