Answer:
Current, [tex]I=45\times 10^3\ A[/tex]
Explanation:
Given that,
Voltage of a battery, V = 9 volts
Resistance, R = 2×10⁻⁴ ohms
We need to find the current flowing in the battery. Let it is I. It can be calculated using Ohm's law as follows :
V = IR
[tex]I=\dfrac{V}{R}\\\\I=\dfrac{9}{2\times 10^{-4}}\\\\I=45000\ A\\\\I=45\times 10^3\ A[/tex]
So, the current is [tex]45\times 10^3\ A[/tex].
