Respuesta :

Simple....

you have: [tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]

To solve for x:

[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]

1.) Isolate the variable "x" (Remove y)


[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
                      [tex]- \frac{5}{6} y[/tex]   [tex]- \frac{5}{6} y[/tex]

Leaving you with....

[tex] \frac{3}{4} x=-\frac{5}{6}y +15[/tex]

2.) Divide by the variable.....

[tex] \frac{ \frac{3}{4}x }{ \frac{3}{4} } = \frac{ -\frac{5}{6}y+15 }{ \frac{3}{4} } [/tex]

Leaving you with...

x=[tex] -\frac{10y}{9} +20[/tex]

Now, solve for y.

To solve for y:

[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]

1.)Isolate the variable "y" (Remove x)

[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex] 
[tex]+ \frac{3}{4} [/tex]   [tex]+ \frac{3}{4} [/tex]

Leaving you with....

[tex] \frac{5}{6} y= \frac{3}{4} x+15[/tex]

2.)Divide by the variable.....

[tex] \frac{ \frac{5}{6}y }{ \frac{5}{6} } = \frac{ \frac{3}{4}x+15 }{ \frac{5}{6} } [/tex]

Leaving you with....

y=[tex] \frac{9x}{10} +18[/tex]

x-intercept: (-20,0)

y-intercept: (0,18)

Thus, your answer.

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