abdulmoeedzayan abdulmoeedzayan
  • 16-12-2020
  • Mathematics
contestada

Prove that (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)=0

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MrNK
MrNK MrNK
  • 16-12-2020

Answer:

x=0 x=y=z. with these presumed variable amounts, one can conclude that the equation you asked is equivalent to 0

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surjithayer10 surjithayer10
  • 16-12-2020

Answer:

Step-by-step explanation:

(x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)

=x²-y²+y²-z²+z²-x²

=0

Answer Link

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