Respuesta :

Answer:

The solutions are 0 and 3

Step-by-step explanation:

x = 3-y

((3-y)^2+y^2)=9

=(y^2-6y+9)+y^2) = 9

= 2y^2 - 6y +9 -9 =0

=2y^2 -6y=0

= y*(2y -6) = 0

y1=0 y2=3

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