Respuesta :

Hrishii

Answer:

[tex] x=\{- \frac{1}{3}\}[/tex]

Step-by-step explanation:

[tex]9x^2 +6x = -1 \\ \\ 9x^2 +6x + 1 = 0\\ \\ {(3x + 1)}^{2} = 0 \\ \\ 3x + 1 = 0 \\ \\ 3x = - 1 \\ \\ x = - \frac{1}{3}\\\\x=\{- \frac{1}{3}\} [/tex]

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