ragahdalfadil334
ragahdalfadil334 ragahdalfadil334
  • 19-12-2020
  • Physics
contestada

how fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5 j


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Respuesta :

nina004
nina004 nina004
  • 19-12-2020

Explanation:

[tex]kinetic \: energy= \frac{1}{2} m {v}^{2} [/tex]

[tex]2 \times {10}^{5} = \frac{1}{2} 1000 {v}^{2} [/tex]

[tex]2 \times {10}^{5} = 500 {v}^{2} [/tex]

[tex] \frac{2 \times {10}^{5} }{500} = {v}^{2} [/tex]

[tex] {v}^{2} = 400[/tex]

[tex]v = 20[/tex]

Answer Link
Enyima Enyima
  • 19-12-2020

Answer:

KE= 1/2mv^2

where KE= 2.0*10^5j

Ver imagen Enyima
Answer Link

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