ragahdalfadil334
ragahdalfadil334 ragahdalfadil334
  • 19-12-2020
  • Physics
contestada

how fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​

Respuesta :

baraa47 baraa47
  • 19-12-2020

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

Answer Link
1beiersim 1beiersim
  • 13-04-2022

Answer:

20m/s

Explanation:

Ek=1/2(m)(v)^2

Ek=2.0x10^5

m=1000kg

v=?

2.0x10^5=1/2(1000)v^2

(2.0x10^5)/(0.5x1000)=v^2

[tex]\sqrt{400}[/tex]=v

20m/s=v

Answer Link

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