Answer:
16
Step-by-step explanation:
How many times more intense is an earthquake measuring 6.8 on the Richter scale than one measuring 5.6?
Given:
Earthquake 1 : magnitude = 6.8
Earthquake 2: magnitude = 5.6
The intensity of an earthquake
I1 / I2
log I1 /s = 6.8
log I2 /s = 5.6
(log I2 /s) - (log I1 /s) = 6.8 - 5.6
(log I2 /s) - (log I1 /s) = 1.2
log(I2 / I1) = 1.2
I2 / I1 = 10^1.2
I2 / I1 = 15.8489
= 16
6.8 earthquake is about 16 times more intense than earthquake measuring 5.6
