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21-02-2021
Mathematics

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2cos60° +3 sin-45° -3 sin 30° +2 cos 90°

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ADVENTUROUSBOY ADVENTUROUSBOY

21-02-2021

2cos60° + 3sin-45° - 3sin30° + 2cos90°

= 2 × 1/2 + 3 × -1/√3 - 3 × 1/2 + 2 ×0

= 1 - 3/√3 - 3/2 + 0

= 1 - 3/√3 - 3/2

= 1 - 3/1.732 - 1.5. <----> ( √3 = 1.732 )

= 1 - 1.732 - 1.5

= -2.232

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