nathaliaasd18 nathaliaasd18

16-11-2016
Mathematics

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Find the standard equation of the circle passing through a given point with a given center . Center (6,3) and passing through (0,-1)

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crisforp crisforp

16-11-2016

The radius of the circle is r = [tex] \sqrt{ (6-0)^{2} + (3-(-1))^{2} } = \sqrt{52} ;[/tex]
The standard equation of the circle is [tex] (x-6)^{2} + (y - 3)^{2} = 52;[/tex]

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