samadhidiaz46
samadhidiaz46 samadhidiaz46
  • 17-03-2021
  • Mathematics
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Given: Parallelogram ABCD,
m DAB = 120', BP = 3x + 7, DP = -x + 17.
Find the following:
a. m DCB

b. BD =

Given Parallelogram ABCD m DAB 120 BP 3x 7 DP x 17 Find the following a m DCB b BD class=

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Аноним Аноним
  • 17-03-2021

Answer:

a. m DCB =<DAB=120 opposite angle of the parallelogram are equal

again

BP=PD diagonal bisect it

3x+7=-x+17

3x+x=17-7

4x=10

x=10/4=5/2

b. BD =3x+7-x+17=3×5/2+7-5/2+17=2×5/2+24=5+24=29

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