Blackstar101
Blackstar101 Blackstar101
  • 16-11-2016
  • Mathematics
contestada

Find the equation of a line in slope-intercept form that passes through the points (-2, 20) and (3, -10).

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Аноним Аноним
  • 16-11-2016
Simple...

you have: (-2,20) and (3,-10,)

Using [tex] \frac{ y_{1}- y_{2} }{ x_{1}- x_{2} } [/tex] to find slope--->>>

[tex] \frac{20--10}{-2-3} = \frac{30}{-5} [/tex]

=-6

m=-6

Using y=mx+b to find the equation of the line-->>>(Use any of the coordinates)

(-2,20)

20=-6(-2)+b

20=12+b

20=12+b
-12  -12

8=b

y=-6x+8

Thus, your answer.




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