Answer:
the time taken for the hammer to hit the ground is 2.26 s.
Step-by-step explanation:
Given;
height through which the hammer falls, h = 25 m
The time taken for the hammer to hit the ground is calculated as;
[tex]h(t) = ut + \frac{1}{2} gt^2\\\\h(t) = 0 + \frac{1}{2} (9.8)t^2\\\\h(t) = 4.9t^2\\\\t = \sqrt{\frac{h(t)}{4.9} } \\\\t = \sqrt{\frac{25}{4.9} } \\\\t = 2.26 \ s[/tex]
Therefore, the time taken for the hammer to hit the ground is 2.26 s.
