jennzzng jennzzng

18-03-2021
Mathematics

contestada

solve 5sin^2x-1=0
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Respuesta :

faisalkhanahmadzai88 faisalkhanahmadzai88

18-03-2021

Answer:

to 1 decimal place,. (a) tan (3x + ... (i) 2cos 2x – 5sin 2x = 0 R cos(2x + λ) = 0 λ = 68.2 ⇒ 2x + 68.2 = 90 B1. 2x + λ = ... (16cos2x – 9)(cos2x – 1) = 0.

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