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What is the rule for the following geometric sequence? 64, -32, 16, -8
A: an=32(-1/2)^n-1
B:an=32(2)^n-1
C:an=32(1/2)^n-1
D:an=32(-2)^n-1

Respuesta :

aeriiiel
Answer:
Correct answer: aₙ = a₁ · 2ⁿ⁻¹
Step-by-step explanation:
Given: Geometric sequence
64, 128, 256, 512, .....
First term a₁ = 64
Second term a₂ = a₁ · 2 = 128
Third term a₃ = a₂ · 2 = a₁ · 2² = 256
Fourth term a₄ = a₃ · 2 = a₁ · 2³ = 512
...................................................
n - th term aₙ = a₁ · 2ⁿ⁻¹
God is with you!!!

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