Respuesta :

surasa

Answer:

18225

Step-by-step explanation:

let 7th term = t7

t7= a.3^(7-1) (common formula of geometric series is a.r^(n-1)

or, 25= a. 3^6

or, a=25/729

now, for 13th term,

t13= a.r^(13-1)

= 25/729 × 3^12

=18225

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