jbohm479
contestada

the electrostatic force between two objects is 40N. if the charge of one object is cut in half, and the distance is doubled, what is the new force?

Respuesta :

Answer:

F1 = K Q1 Q2 / R1^2

F2 = K Q1 / 2 * Q2 / (2 R1)^2

F2 / F1 = 1/2 / 4 = 1/8

The new force is 5N   (1/2 due to charge and 1/4 due to distance)