sophiacarmenat
contestada

2. Write the equation of the circle with a center at
(-2, -8) and a radius of v10.

A. (x + 2)^2 + (y + 8)^2 = 25
B. (x - 2)^2 + (y – 8)^2 = 10
C. (x + 2)^2 + (y + 8)^2 = 10
D. (x + 2)^2 + (y + 8)^2 = 100
E. (x - 2)^2 + (y - 3)^2 = 100

Respuesta :

Hrishii

Answer:

C. [tex] (x +2) ^2 +(y+8)^2 =10 [/tex]

Step-by-step explanation:

Center of the circle (h, k) = (-2, - 8)

Radius [tex] r=\sqrt {10}[/tex]

Equation of circle in center radius form is given as:

[tex] (x - h) ^2 +(y-k) ^2 =r^2 [/tex]

Plugging the values of h, k and r in the above equation, we find:

[tex] [x - (- 2)] ^2 +[y-(-8) ]^2 =(\sqrt {10})^2 [/tex]

[tex] (x +2) ^2 +(y+8)^2 =10 [/tex]

Otras preguntas