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AB and BC form a right angle at point B. If A=(-3,-1) and B=(4,4), what is the equation of BC
A. X+3y=16
B. 2x+y=12
C. -7x-5y=-48
D. 7x-5=48

Respuesta :

Medunno13

Answer: D. -7x-5y=-48

Step-by-step explanation:

The slope of AB is [tex]\frac{-1-4}{-3-4}=\frac{5}{7}[/tex]. Since perpendicular lines have slopes that are negative reciprocals, the slope of BC is -7/5.

Substituting into point-slope form,

[tex]y-4=-\frac{7}{5}(x-4)\\\\5y-20=-7(x-4)\\\\5y-20=-7x+28\\\\\boxed{-7x-5y=-48}[/tex]

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