saraharbs saraharbs
  • 16-05-2021
  • Mathematics
contestada

tanθ=

a. 1 - cot^2 θ
b. 1/cot θ
c. 1 + sec^2 θ

Respuesta :

msm555
msm555 msm555
  • 16-05-2021

Answer:

[tex]tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ} [/tex]

b. 1/cot θ

Answer Link
Аноним Аноним
  • 16-05-2021

Answer:

[tex]tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ} [/tex]

Answer Link

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