Answer:
∠P ≅ ∠R
Step-by-step explanation:
We can see here two triangles , ∆ PQS and ∆ RQS.
To Prove :-
We can prove the given two triangles congruent then we can easily prove it out.
In ∆ PQS and ∆ RQS
- PQ = QR ( given )
- QS = QS ( common)
- ∠PQS = ∠ RQS .
Therefore by SAS congruence condition , both triangles are congruent .
Hence ,
- ∠P ≅ ∠R ( by corresponding parts of congruent ∆s)
Hence Proved !
