centenoherrerajennif
centenoherrerajennif centenoherrerajennif
  • 17-05-2021
  • Physics
contestada

The speed of light in a piece of plastic is 1.87 × 10^8 meters per second. What is the absolute index of refraction of this plastic?
options:
1.0
1.6
0.67
1.33

Respuesta :

hamzaahmeds
hamzaahmeds hamzaahmeds
  • 23-05-2021

Answer:

n = 1.6

Explanation:

The formula for the calculation of the absolute index of refraction is given as follows:

[tex]n = \frac{c}{v}[/tex]

where,

n = index of refraction

c = speed of light in vacuum = 3 x 10⁸ m/s

v = speed of light in the piece of plastic = 1.87 x 10⁸ m/s

Therefore,

[tex]n = \frac{3\ x\ 10^8\ m/s}{1.87\ x\ 10^8\ m/s}[/tex]

n = 1.6

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