gaboalejandro6782 gaboalejandro6782
  • 17-05-2021
  • Physics
contestada

75 J of heat are added to a heat engine and 50 J of thermal energy is lost in the process. Determine the work done by the engine (in Joules)?

Respuesta :

onyebuchinnaji
onyebuchinnaji onyebuchinnaji
  • 17-05-2021

Answer:

The work done by the engine is 50 J.

Explanation:

Given;

amount of heat energy added to the heat engine, Q = 75 J

energy lost in the process, E = 50 J

let the work done by the engine (system) = W

Apply the first law of thermodynamic;

ΔU = Q - W

where;

ΔU is change in internal energy = 75 J - 50 J = 25 J

25 = 75 - W

25 - 75 = - W

-50 J = - W

W = 50 J

Therefore, the work done by the engine is 50 J.

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