Answer:
[tex]M_{base}=6M[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about titration, which base solved by knowing that the HCl reacts with the NaOH in a 1:1 mole ratio, and therefore, we can write the following:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
Thus, we solve for the molarity of the base, NaOH, as shown below:
[tex]M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{3L*2M}{1.00L}\\\\M_{base}=6M[/tex]
Regards!
