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2.
Which of the following aqueous solutions contains the same number of solute particles as are
contained in 250 cm of 2.0 mol dm potassium chloride?
A. 250 cm² of 2.0 mol dm3 calcium chloride solution.
B. 250 cm3 of 2.0 mol dm potassium sulphate solution
C. 500 cm' of 1.0 mol dmº magnesium sulphate solution.
D. 1000 cm3 of 2.0 mol dm of aqueous ethanol.

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Answer:

C. 500 cm' of 1.0 mol dmº magnesium sulphate solution.

Explanation:

Let us look at each of the solutions individually;

CaCl2  has three particles

K2SO4 has three particles

MgSO4 has two particles

C2H5OH has only one particle

The number of moles of moles in 250 cm of 2.0 mol dm-3 potassium chloride is 250/1000 * 2 = 0.5 moles having two particles

Also; number of moles in 500 cm' of 1.0 mol dm-3 magnesium sulphate solution= 500/1000 * 1 = 0.5 moles having two particles

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