Answer:
The two shortest diagonals seems to be RU and TS. A further explanation is provided below.
Step-by-step explanation:
The given coordinated are:
r = (1, 1)
s = (6, 1)
t = (8, 5)
u = (3, 3)
Now,
The distance between RU will be:
= [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
On putting the values, we get
= [tex]\sqrt{(3-1)^2+(3+1)^2}[/tex]
= [tex]\sqrt{(2)^2+(4)^2}[/tex]
= [tex]\sqrt{4+16}[/tex]
= [tex]\sqrt{20}[/tex]
