Answer: [tex]322\ lb[/tex]
Step-by-step explanation:
Given
The magnitude of the force [tex]F=350\ \text{Pounds}[/tex]
The force makes an angle of [tex]67^{\circ}[/tex] with the horizontal
So, the components of the force are
[tex]\Rightarrow F\cos 67^{\circ}, F\sin 67^{\circ}\\\Rightarrow F\cos 67^{\circ}=350\cos 67^{\circ}\\\quad \quad =136.75\ lb\\\text{Similarly, }\\\Rightarrow F\sin 67^{\circ}=350\sin 67^{\circ}\\=322.17\ lb[/tex]
The larger among the two is [tex]F\sin 67^{\circ}[/tex] i.e. [tex]322\ lb[/tex]
