montanakevin montanakevin
  • 19-05-2021
  • Mathematics
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racionaliza

√7 + 2√5 ÷√7 −√5

Respuesta :

sreedevi102
sreedevi102 sreedevi102
  • 20-05-2021

Answer:

[tex]\frac{\sqrt{7} +2\sqrt{5}}{\sqrt{7}-\sqrt{5} }\\\\=\frac{\sqrt{7} +2\sqrt{5}}{\sqrt{7}-\sqrt{5} }*\frac{\sqrt{7} +\sqrt{5}}{\sqrt{7}+\sqrt{5} }\\\\ =\frac{(\sqrt{7} +2\sqrt{5})(\sqrt{7} + \sqrt{5} )}{(\sqrt{7}-\sqrt{5})(\sqrt{7}+\sqrt{5})\\ }\\\\=\frac{17 +3\sqrt{35} }{2}[/tex]

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