Respuesta :

VirαtKσhli

Answer:

2π

Step-by-step explanation:

Given :-

  • y = 2 sinθ - 3

And we need to find out the period of it . Now using the form ,

[tex]:\implies[/tex] y = a sin ( bx - c ) + d

On comparing we have ,

  • a = 2
  • b = 1
  • c = 0
  • d = -3

We can find the period using formula ,

[tex]:\implies[/tex] Period = 2π/ |b|

[tex]:\implies[/tex] Period = 2π/|1|

[tex]:\implies[/tex] Period = 2π

Hence the period is 2π .

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