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18-09-2021
Mathematics

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Given f(x)=2x^2-3x+1, determine the value of 3f(-2x)

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tewodroshabtamu29 tewodroshabtamu29

18-09-2021

Answer:

Step-by-step explanation:

3f(-2x)= 3[2(-2x)^2-3(-2x)+1]

=3[2(4x^2)+6x+1]

=3[8x^2+6x+1]

=24x^2+18x+3

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