Rociepaa6nd9a Rociepaa6nd9a

19-12-2016
Mathematics

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(4n^2 3n) (2n^3-4) (3n^2-2n) ?

Respuesta :

tibboyz123 tibboyz123

19-12-2016

(4n² 3n ) = 12n³

(12n³) (2n³-4) (3n²-2n) = (24n^6 - 48n³) (3n²-2n)
= 72n^8 - 48n^7 - 144n^5 + 96n^4

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