Respuesta :

Step-by-step explanation:

Logx + Log(x+3)=2log(x+1)

Log x(x+3) = Log (x+1)²

x(x+3)=(x+1)²

x²+3x = x²+2x+1

delete x², we find

3x = 2x+1

3x-2x = 1

x = 1