kyndallnicholegregor kyndallnicholegregor

20-10-2021
Mathematics

contestada

How do I solve 5x - 4x^2

Respuesta :

inspirationalgdandyt inspirationalgdandyt

20-10-2021

Answer:

If you are asking,

5x - 4x^2=0

x(5-4x)=0

Either,

x=0

or,

5-4x=0

x=5/4

If factor,

5x - 4x^2

x(5-4x)

If difference,

5x - 4x^2

The same as they are not like terms.

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