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Find the value of xxx in the isosceles triangle shown below.

Choose 1 answer:
Choose 1 answer:

(Choice A)
A
x = 4x=4x, equals, 4

(Choice B)
B
x = \sqrt{11}x=
11
​
x, equals, square root of, 11, end square root

(Choice C)
C
x = 15x=15x, equals, 15

(Choice D)
D
x=\sqrt{61}x=
61
​

Respuesta :

MrRoyal

An isosceles triangle has two congruent sides and angles

The value of x in the isosceles triangle is

How to determine the value of x

To calculate the value of x, we make use of the following Pythagoras theorem

[tex]x = \sqrt{4^2 + (6/2)^2[/tex]

So, we have:

[tex]x = \sqrt{4^2 + 3^2[/tex]

Evaluate the squares

[tex]x = \sqrt{16 + 9[/tex]

[tex]x = \sqrt{25[/tex]

Evaluate the exponent

[tex]x = 5[/tex]

Hence, the value of x is 5

Read more about isosceles triangles at:

https://brainly.com/question/1475130

Ver imagen MrRoyal

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