Given: (x1, y1) = (4, 2) and Parallel to y = 2x + 2
y=mx+c -> m is known as the gradient which in this case is 2
As the line is parallel to y = 2x + 2, it will also have a slope of 2.
The point-slope formula states (y − y1) = m (x − x1)
Substituting the values of m = 2 and (x1, y1) = (4, 2) in the above equation we get,
⇒ (y - 2) = 2(x - 4)
⇒ y - 2 = 2x - 8
⇒ y = 2x - 6
I hope this is right
