angeljomarsal2021
angeljomarsal2021 angeljomarsal2021
  • 22-01-2022
  • Mathematics
contestada

Please help anyone I need help

Please help anyone I need help class=

Respuesta :

JennyTheBest813
JennyTheBest813 JennyTheBest813
  • 26-01-2022

Answer:

3

Step-by-step explanation:

We can use 2 for x and 4 for y.

(2y-2)/x

(2(4)-2)/2

(8-2)/2

6/2

3

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