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In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9 feet long?

In this fulcrum the weights are perfectly balanced How far must the fulcrum be located from the 40 lb weight if the bar is 9 feet long class=

Respuesta :

yashddsy26
so...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
calculista

Answer:

[tex]x=5\ ft[/tex]

Step-by-step explanation:

we know that

The bar is [tex]9[/tex] feet long

so

[tex]x+(x-1)=9[/tex]

Solve for x

[tex]2x-1=9[/tex]

[tex]2x=10[/tex]

[tex]x=5\ ft[/tex]

Verify

[tex]40x=50(x-1)[/tex]

substitute the value of x

[tex]40(5)=50(5-1)[/tex]

[tex]40(5)=50(4)[/tex]

[tex]200=200[/tex] -----> the weights are perfectly balanced

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