Srukook
Srukook Srukook
  • 20-02-2022
  • Mathematics
contestada

144000x²+431974x-39=0 find the value of X​

Respuesta :

semsee45
semsee45 semsee45
  • 20-02-2022

Answer:

[tex]x=0.00009028, x=-2.999909725[/tex]

Step-by-step explanation:

Use the quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

when [tex]ax^2+bx+c=0[/tex]

Therefore, for [tex]144000x^2+431974x-39=0[/tex]

a = 144,000   b = 431,974  and c = -39

Substituting this data into the quadratic formula:

[tex]x=\dfrac{-431974 \pm \sqrt{431974^2-4(144000)(-39)} }{2(144000)}[/tex]

[tex]x=0.00009028, x=-2.999909725[/tex]

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