Respuesta :

PsychrolutesMarcidus
y= -6x² +3x +2

Using the quadratic equation x= [tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex]

We assign variables a,b,c as follows with the form ax²+bx +c

a= -6
b= 3
c=2

By plugging in the variable in the quadratic equation we can find x

[tex]x= \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex]
=[tex]\frac{-3+- \sqrt{3^2-4(-6)(2)} }{2(-6)} [/tex]

If you simplify the equation you will have two real solutions for x

[tex] \frac{-3+- \sqrt{9+48} }{-12} [/tex]
[tex] \frac{-3+- \sqrt{57} }{-12}[/tex]

As a square root can be positive or negative, two solutions are possible
Hence,
[tex]x = \frac{-3+\sqrt{57} }{-12}, \frac{-3- \sqrt{57} }{-12}[/tex]

Which can be further simplified to

[tex]x = \frac{\sqrt{57} }{4}, \frac{- \sqrt{57} }{4}[/tex]

TAA DAAA! :)
PS if you rate my answer as "Brainliest" that would be most appreciated

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