qcesticn
qcesticn qcesticn
  • 21-01-2017
  • Mathematics
contestada

how do i put f(x) = -x^2 + 8x + 9 in vertex form?

Respuesta :

christinaS christinaS
  • 21-01-2017
the answer would be y=(x-4)^2+25
Answer Link
apologiabiology
apologiabiology apologiabiology
  • 21-01-2017
vertex form is y=a(x-h)²+k

complete the square


f(x)=(-x²+8x)+9
undistribute -1
f(x)=-1(x²-8x)+9
take 1/2 of -8 and square it to get 16, then add neagative and positive inside
f(x)=-1(x²-8x+16-16)+9
complete the square
f(x)=-1((x-4)²-16)+9
expand
f(x)=-1(x-4)²+16+9
f(x)=-1(x-4)²+25

vertex form is
f(x)=-1(x-4)²+25
Answer Link

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