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1 An object rests on a rough surface and is pushed horizontally with force of 6 N.
The mass of the object is 5 kg and the coefficient of friction between the object and
the surface is 0.3.

1)The horizontal force acting on the object is increased to PN. Find the largest
value of P for which the object does not slip.

Respuesta :

The normal force acting on the body is 49.05N

Data;

  • force = 6N
  • mass = 5kg
  • coefficient of friction = 0.3

Horizontal Force

To calculate the horizontal force or the force acting on the horizontal plane on the body is given as

[tex]N + fsin\theta = mg[/tex]

Where N = normal force

Let's substitute the values and solve.

[tex]N = mg - fsin\theta\\N = (5 * 9.81) - 6 sin (0)\\N = 49.05N[/tex]

The normal force acting on the body is 49.05N

Learn more on normal force here;

https://brainly.com/question/10941832

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