iandr99 iandr99
  • 19-04-2022
  • Mathematics
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f(x)=2x^3-6x+k and the remainder when f(x) is divided by x+1=7 then what is the value of k

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thapapancha5
thapapancha5 thapapancha5
  • 19-04-2022

Given: f(x)=2x(cube)-6x+x

reaminder of f(x) when (x+1) diveded

to find value of k

solution,

f(x)=2x(cube)-6x+k

f(-1)=7

2(-1)(cube)+6+k=7

4+x=7

k=7

Hence,k=7

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