arielascuy12386
arielascuy12386 arielascuy12386
  • 20-04-2022
  • Mathematics
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please help me on this thanks

please help me on this thanks class=

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loneguy
loneguy loneguy
  • 20-04-2022

[tex]\cos \angle H =\dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{IH}{GH}=\dfrac{28}{53}[/tex]

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